Neco Gce 2016 Physics Practical Answers – Nov/Dec Expo

PHYSICS PRACTICAL ANSWERS [Da_CYBER ] NOTE THAT SUBSCRIBERS GETS THE ANSWERS FIRST BEFORE ITS BEEN POSTED HERE – ALWAYS SUBSCRIBE IF YOU NEED FAST AND EARLY RUNS




(1a)
PLS DRAW A TABLE:


i|Mi(cm)|Mi(g)|Li(cm)(Raw)|Li(cm)(Real)|e=li-lo:1|4.75 |47.50 |2.60|5.20 |1.40|2|6.13 |61.30 |3.15|6.30 |2.50|3|8.53 |85.80 |3.72|7.40 |3.60|4|10.43|104.30|4.30|8.60 |4.80|5|12.28|122.80|4.85|9.70 |5.90|6|14.20|142.00|5.40|10.80|7.00|


Slope= De(cm)/DM(g) = e2-e1/M2-M1





(1aviii)-I avoided parallex error when taking the reading-I would ensure that the masses do not touch the ground.-I would ensure that the support is rigid






(1bi) This means that the ratio of force to extension is 10Nm-1


(1bii) E = 1/2Ke^2but F=ke.:. E = F/kE= 1/2k(F/K)^2E=F^2/2k


===================(3ai)TABULATEi|X(n)|Y(n)|V(v)|Z=V^-1|R(n)1|2|2|1.50|0.67|1.002|6|3|1.30|0.77|2.003|12|4|1.14|0.88|3.004|20|5|1.00|1.00|4.005|30|6|0.91|1.10|5.00



Precaution:-I will ensure tight connections of all wires-i would ensure that the key is openedduring each reading


(3bi)R=(2*3)/(2 3) 0.8R=1.20 0.8R=2.0ohmsBut I=E.M.F/R rI=E/2 r2I Ir=EIr=E-2Ir=(E-2I)/I


(3bii)V=IR=2.6*4V=10.40volts


MORE NSWERS COMING....


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