2ai)
fo=15cm
2av)
a=60.00cm
b=20.00cm
Hence L=a/b=60.00/20.00
L=3
2avi)
TABULATE
S/N:1,2,3,4,5
b(cm):20.00,25.00,35.00,40.00
a(cm):60.00,37.50,30.00,26.25,24.00
L=a/b:3.00,1.50,1.00,0.75,0.60
2avii)
Slope=Change in L/Change in a
=(3-0.25)/(60-18.6)
=2.75/41.4
=0.006642
2aviii)
S^-1=1/S
=(1/0.0066425cm)
S=15.05
S=15cm
2bi)
he characteristics of imaged formed are .
i)It is virtual
ii) It is enlarged or magnified i.e. twice or two
times bigger as the object(m=2)
2bII)
The concave mirror ,mounted in its holder
,is moved to and fro in front of the until a sharp
image of the cross wire of the ray box is formed
on the screen adjacent to the object .The
distance between the mirror and the screen was
measured as 30.1cm.Since the radius of the
curvature r,=2fo ,then half this distance is the
focal length of the mirror fo .Thus focal length
was determined to be 15.05cm approximately
15cm
3a)
Vo=0.35V
TABULATE
S/N:1,2,3,4,5,6
R(ohm):1.0,2.0,3.0,4.0,5.0,6.0
V(v):1.40,1.65,1.80,2.00,2.10,2.15
R^-1(ohm^-1):1.000,0.500,0.333,0.200,0.167.
V^-1(v^-1).0.714,0.606,0.556,0.500,0.476,0.465
DRAW THE GRAPH of V^-1(v^-1) against R^-1
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Title :
NECO 2017/2018 QUESTIONS AND ANSWERS
Description : 2ai) fo=15cm 2av) a=60.00cm b=20.00cm Hence L=a/b=60.00/20.00 L=3 2avi) TABULATE S/N:1,2,3,4,5 b(cm):20.00,25.00,35.00,40.00 a(cm):60.00,37....
Rating :
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